3.2(x+4)+2^2+1.7(x-3)=27

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Solution for 3.2(x+4)+2^2+1.7(x-3)=27 equation: 



3.2(x+4)+2^2+1.7(x-3)=27

We move all terms to the left:

3.2(x+4)+2^2+1.7(x-3)-(27)=0

determiningTheFunctionDomain
3.2(x+4)+1.7(x-3)-27+2^2=0

We add all the numbers together, and all the variables

3.2(x+4)+1.7(x-3)-23=0

We multiply parentheses

3.2x+1.7x+12.8-5.1-23=0

We add all the numbers together, and all the variables

4.9x-15.3=0

We move all terms containing x to the left, all other terms to the right

4.9x=15.3

x=15.3/4.9

x=3+0.6/4.9

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